Optimal. Leaf size=661 \[ -\frac{27\ 3^{3/4} \left (1-\sqrt{3}\right ) a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) \text{EllipticF}\left (\cos ^{-1}\left (\frac{\sqrt [3]{a}+\left (1-\sqrt{3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x}\right ),\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{23296 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{81 \left (1+\sqrt{3}\right ) a^3 e \sqrt{e x} \sqrt{a+b x^3} (26 A b-5 a B)}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )}-\frac{81 \sqrt [4]{3} a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) E\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{11648 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{27 a^2 (e x)^{5/2} \sqrt{a+b x^3} (26 A b-5 a B)}{5824 b e}+\frac{(e x)^{5/2} \left (a+b x^3\right )^{5/2} (26 A b-5 a B)}{260 b e}+\frac{3 a (e x)^{5/2} \left (a+b x^3\right )^{3/2} (26 A b-5 a B)}{728 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e} \]
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Rubi [A] time = 0.707938, antiderivative size = 661, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {459, 279, 329, 308, 225, 1881} \[ \frac{81 \left (1+\sqrt{3}\right ) a^3 e \sqrt{e x} \sqrt{a+b x^3} (26 A b-5 a B)}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )}-\frac{27\ 3^{3/4} \left (1-\sqrt{3}\right ) a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) F\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{23296 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}-\frac{81 \sqrt [4]{3} a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) E\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{11648 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{27 a^2 (e x)^{5/2} \sqrt{a+b x^3} (26 A b-5 a B)}{5824 b e}+\frac{(e x)^{5/2} \left (a+b x^3\right )^{5/2} (26 A b-5 a B)}{260 b e}+\frac{3 a (e x)^{5/2} \left (a+b x^3\right )^{3/2} (26 A b-5 a B)}{728 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e} \]
Antiderivative was successfully verified.
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Rule 459
Rule 279
Rule 329
Rule 308
Rule 225
Rule 1881
Rubi steps
\begin{align*} \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx &=\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac{\left (-13 A b+\frac{5 a B}{2}\right ) \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \, dx}{13 b}\\ &=\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac{(3 a (26 A b-5 a B)) \int (e x)^{3/2} \left (a+b x^3\right )^{3/2} \, dx}{104 b}\\ &=\frac{3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac{\left (27 a^2 (26 A b-5 a B)\right ) \int (e x)^{3/2} \sqrt{a+b x^3} \, dx}{1456 b}\\ &=\frac{27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt{a+b x^3}}{5824 b e}+\frac{3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac{\left (81 a^3 (26 A b-5 a B)\right ) \int \frac{(e x)^{3/2}}{\sqrt{a+b x^3}} \, dx}{11648 b}\\ &=\frac{27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt{a+b x^3}}{5824 b e}+\frac{3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac{\left (81 a^3 (26 A b-5 a B)\right ) \operatorname{Subst}\left (\int \frac{x^4}{\sqrt{a+\frac{b x^6}{e^3}}} \, dx,x,\sqrt{e x}\right )}{5824 b e}\\ &=\frac{27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt{a+b x^3}}{5824 b e}+\frac{3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac{\left (81 a^3 (26 A b-5 a B)\right ) \operatorname{Subst}\left (\int \frac{\left (-1+\sqrt{3}\right ) a^{2/3} e^2-2 b^{2/3} x^4}{\sqrt{a+\frac{b x^6}{e^3}}} \, dx,x,\sqrt{e x}\right )}{11648 b^{5/3} e}-\frac{\left (81 \left (1-\sqrt{3}\right ) a^{11/3} (26 A b-5 a B) e\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+\frac{b x^6}{e^3}}} \, dx,x,\sqrt{e x}\right )}{11648 b^{5/3}}\\ &=\frac{27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt{a+b x^3}}{5824 b e}+\frac{81 \left (1+\sqrt{3}\right ) a^3 (26 A b-5 a B) e \sqrt{e x} \sqrt{a+b x^3}}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )}+\frac{3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac{(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac{81 \sqrt [4]{3} a^{10/3} (26 A b-5 a B) e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\cos ^{-1}\left (\frac{\sqrt [3]{a}+\left (1-\sqrt{3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{11648 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}-\frac{27\ 3^{3/4} \left (1-\sqrt{3}\right ) a^{10/3} (26 A b-5 a B) e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} F\left (\cos ^{-1}\left (\frac{\sqrt [3]{a}+\left (1-\sqrt{3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{23296 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}\\ \end{align*}
Mathematica [C] time = 0.133452, size = 99, normalized size = 0.15 \[ \frac{x (e x)^{3/2} \sqrt{a+b x^3} \left (a^2 (26 A b-5 a B) \, _2F_1\left (-\frac{5}{2},\frac{5}{6};\frac{11}{6};-\frac{b x^3}{a}\right )+5 B \sqrt{\frac{b x^3}{a}+1} \left (a+b x^3\right )^3\right )}{65 b \sqrt{\frac{b x^3}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.061, size = 6202, normalized size = 9.4 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{5}{2}} \left (e x\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (B b^{2} e x^{10} +{\left (2 \, B a b + A b^{2}\right )} e x^{7} +{\left (B a^{2} + 2 \, A a b\right )} e x^{4} + A a^{2} e x\right )} \sqrt{b x^{3} + a} \sqrt{e x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{5}{2}} \left (e x\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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